Question

2NH3+22 kcal=N2+ 6H
how much heat energy must be absorbed during the production of 9 moles of hydrogen gas?
please help, I'm stuck with where to start the equation!

Answer 1

the equation, as is written, is incorrect. It should read:

\(2NH_3+~22 kcal\rightleftharpoons N_2+ 6H_2\)

now we need to use the coefficient for hydrogen gas,

\(\sf Energy~absorbed=\dfrac{moles~of~H_2}{H_2's~coefficient}*E_{reaction}\)

\(\sf Energy~absorbed=\dfrac{9~moles}{6}*22~kcal/mol=\dfrac{9*22}{6}~ kcal \)