Will medal and fan, equation in question
\[\frac{ 1 }{ x+4 }=\frac{ 1 }{ x ^{2}+3x-4 }+\frac{ 4 }{ x-1 }\]
Step 1: Factor (hint: use the denominators of the other fractions as a suggestion for possible factors of the quadratic form)\[\frac{1}{x+4}=\frac{1}{(x+4)(x-1)}+\frac{4}{x-1}\]Step 2: Multiply the whole equation by (x+4)(x-1) to eliminate all the denominators \[\frac{(x+4)(x-1)}{x+4}=\frac{(x+4)(x-1)}{(x+4)(x-1)}+\frac{4(x+4)(x-1)}{x-1}\]\[(x-1)=1+4(x+4)\]Step 3: Simplify \[x=2+4x+16\]\[x=18+4x\]\[-3x=18\]Therefore: \[x=-6\]
Finally once you get an answer to an algebra problem you should ALWAYS check to make sure it satisfies the original problem. I.e. substitute x=-6 into the the very first equation and make sure you get something that makes sense like: 1=1 -(2/3)=-(2/3) etc If you get nonsense like 1=3 -5=5 Then something went wrong and you should recheck your calculation. Please note this is the single EASIEST way to make sure you got the right answer.
Thank you so much :3 this really helped out and i understand much better
Join our real-time social learning platform and learn together with your friends!