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determine between which consecutive integers one or more real zeros of f(x)=-x^3+2x^2-x-5 are located
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I'll assume you can't use a calculator for this, otherwise you can find the zero. Without a calculator, you can use the location principle. Plug in consecutive integers for x. The answer will be the two integers in which one gives you a positive value and one gives you a negative value. Start by trying the integers -3,-2,-1,0,1,2,3 for x. f(-3)= -44, f(-2)=-13, f(-1)= -2, f(0)=1. The graph is below the x-axis at x=-1, and above it at x=0, so it must have crossed the x-axis between x= -1 and x= 0. This is the only real zero of the function.
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