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Mathematics
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OpenStudy (ivysleague):
PLEASE HELP. MATH DUE IN 10 MIN. HELP.
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OpenStudy (alexandervonhumboldt2):
we cannot help on tests
OpenStudy (ivysleague):
This is not a test.
OpenStudy (ivysleague):
I have to leave in 10 minutes to go eat dinner.
OpenStudy (ivysleague):
It's TenMarks, will you help me?
OpenStudy (mathwizzard3):
I can try
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OpenStudy (mathwizzard3):
just tell me what it is
OpenStudy (ivysleague):
thank you.
OpenStudy (ivysleague):
OpenStudy (anonymous):
its b
OpenStudy (mathwizzard3):
yeah
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OpenStudy (ivysleague):
OpenStudy (mathwizzard3):
D
OpenStudy (mathwizzard3):
wait that might not be the answer
OpenStudy (anonymous):
its -5
OpenStudy (mathwizzard3):
yeah oops sorry
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OpenStudy (anonymous):
how did you get -5
OpenStudy (ivysleague):
OpenStudy (anonymous):
coz if u want the x to be at the bottom it has to be a -ve and when u factorize u want the power of five to be able to be factorised out
OpenStudy (ivysleague):
btw, thanks
OpenStudy (anonymous):
ooh okay i see what you did
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OpenStudy (mathwizzard3):
not sure about the next one but I'm kinda slow at figuring things out so I'm gonna let them help you :P GL
OpenStudy (anonymous):
for \[\sqrt{7}\] it is \[7^{1/2}\]
OpenStudy (anonymous):
for the second one it is \[5^{3/7}\]
OpenStudy (ivysleague):
Ohhh I see thanks I got the rest ... on this page
OpenStudy (anonymous):
for the last one
\[\sqrt[7]{3}\]
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OpenStudy (ivysleague):
thank you
OpenStudy (anonymous):
no probs
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