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Mathematics 20 Online
OpenStudy (ivysleague):

PLEASE HELP. MATH DUE IN 10 MIN. HELP.

OpenStudy (alexandervonhumboldt2):

we cannot help on tests

OpenStudy (ivysleague):

This is not a test.

OpenStudy (ivysleague):

I have to leave in 10 minutes to go eat dinner.

OpenStudy (ivysleague):

It's TenMarks, will you help me?

OpenStudy (mathwizzard3):

I can try

OpenStudy (mathwizzard3):

just tell me what it is

OpenStudy (ivysleague):

thank you.

OpenStudy (ivysleague):

OpenStudy (anonymous):

its b

OpenStudy (mathwizzard3):

yeah

OpenStudy (ivysleague):

OpenStudy (mathwizzard3):

D

OpenStudy (mathwizzard3):

wait that might not be the answer

OpenStudy (anonymous):

its -5

OpenStudy (mathwizzard3):

yeah oops sorry

OpenStudy (anonymous):

how did you get -5

OpenStudy (ivysleague):

OpenStudy (anonymous):

coz if u want the x to be at the bottom it has to be a -ve and when u factorize u want the power of five to be able to be factorised out

OpenStudy (ivysleague):

btw, thanks

OpenStudy (anonymous):

ooh okay i see what you did

OpenStudy (mathwizzard3):

not sure about the next one but I'm kinda slow at figuring things out so I'm gonna let them help you :P GL

OpenStudy (anonymous):

for \[\sqrt{7}\] it is \[7^{1/2}\]

OpenStudy (anonymous):

for the second one it is \[5^{3/7}\]

OpenStudy (ivysleague):

Ohhh I see thanks I got the rest ... on this page

OpenStudy (anonymous):

for the last one \[\sqrt[7]{3}\]

OpenStudy (ivysleague):

thank you

OpenStudy (anonymous):

no probs

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