Question

The number of people in a town of 10,000 who have heard a rumor started by a small group of people is given by the following function:

N(t) = 10,000/(5 + 1245e^-.97t)
15. How many people have heard the rumor after 1 day? After 5 days?




16. How long before 1000 of the people in the town have heard the rumor?

Answer 1

@jim_thompson5910 can you help?

Answer 2

what did you get when you plugged in t = 1 ?

Answer 3

i got 2, i dont think i got it right @jim_thompson5910

Answer 4

that's too small. How did you type it into your calc?

Answer 5

N(1)=10000/5+1245e^-.97(1)

Answer 6

N(t) = 10000/(5+1245*e^(-0.97*t))

N(1) = 10000/(5+1245*e^(-0.97*1)) ... replace t with 1

so you should type in `10000/(5+1245*e^(-0.97*1))` into your calc

Answer 7

20.9661898567944051

Answer 8

yep, round that to the nearest whole number

Answer 9

now repeat what you just did, but do it for t = 5 now

Answer 10

21 people in 1 day and 678 people in 5 days

Answer 11

@jim_thompson5910

Answer 12

correct

Answer 13

for #16, you'll need to solve the equation

\[\Large 1,000 = \frac{10,000}{5+1245e^{-0.97t}}\]

for t

Answer 14

i got 5.6876 rounded it would be 6 days @jim_thompson5910

Answer 15

you nailed it

Answer 16

Great! thanks!

Answer 17

you're welcome