Question

Simplify 9 over quantity of 3 minus 2 i

Answer 1

is your problem

\[\frac{ 9 }{ 3-2i }?\]

Answer 2

Yes

Answer 3

mutlpy by a congugate:
conngugete of 3-2i=3+2i

Answer 4

you mean put it into the complex number form?

Answer 5

\[\frac{ 9 }{ 3-2i }*\frac{ 3+2i }{ 3+2i}=\frac{ 9*(3+2i) }{ 3^2-(2i)^2 }=simplify\]

Answer 6

do you need to rationolize the denominator? or what? yeah

Answer 7

5/5 = 40/ 5? Is that correct

Answer 8

yeah i^2=-1

put that into the complex number form prolly

a + b*i

Answer 9

(27+18i) / (9 - 4(-1))

27/13 + (18/13) *i

Answer 10

The options are
Simplify 9 over quantity of 3 minus 2 i.

quantity of negative 27 minus 18 i over 13
9 i over quantity of 2 plus 3 i
quantity of 27 plus 18 i over 5
quantity of 27 plus 18 i over 13

Answer 11

hint:
\[\frac{ 27 }{ 13 }+\frac{ 18 }{ 13 }i=\frac{ 27+18i }{ 13 }\]

Answer 12

I'm trying to figure it out

Answer 13

How did you get 13?