Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Desperately need help with this calculus question!

OpenStudy (anonymous):

OpenStudy (anonymous):

The hint was that dx equals 4/n and x_i equals 4i/n

jimthompson5910 (jim_thompson5910):

Do you have this so far? \[\Large f(x) = \frac{x^2}{4} + 6\] \[\Large f\left(x_i\right) = \frac{\left(x_i\right)^2}{4} + 6\] \[\Large f\left(x_i\right) = \frac{\left(\frac{4i}{n}\right)^2}{4} + 6\]

OpenStudy (anonymous):

Yes!

jimthompson5910 (jim_thompson5910):

ok what do you get when you simplify that?

OpenStudy (anonymous):

\[\left( 4*i \right)^{2}/n ^{2}+6\]

jimthompson5910 (jim_thompson5910):

you forgot about the 4 down below

jimthompson5910 (jim_thompson5910):

Here is what I get \[\Large f(x) = \frac{x^2}{4} + 6\] \[\Large f\left(x_i\right) = \frac{\left(x_i\right)^2}{4} + 6\] \[\Large f\left(x_i\right) = \frac{\left(\frac{4i}{n}\right)^2}{4} + 6\] \[\Large f\left(x_i\right) = \frac{\frac{16i^2}{n^2}}{4} + 6\] \[\Large f\left(x_i\right) = \frac{16i^2}{4n^2} + 6\] Hopefully you agree?

OpenStudy (anonymous):

Yup, I cancelled out the 4 in the denominator

jimthompson5910 (jim_thompson5910):

oh right, then you'd have \[\Large f\left(x_i\right) = \frac{4i^2}{n^2} + 6\]

jimthompson5910 (jim_thompson5910):

\[\Large R_n = \sum_{i=1}^{n}f\left(x_i\right)\Delta x\] \[\Large R_n = \sum_{i=1}^{n}\left(\frac{4i^2}{n^2} + 6\right)*\frac{4}{n}\] \[\Large R_n = \sum_{i=1}^{n}\left(\frac{4i^2}{n^2}*\frac{4}{n} + 6*\frac{4}{n}\right)\] \[\Large R_n = \sum_{i=1}^{n}\left(\frac{4i^2}{n^2}*\frac{4}{n}\right) + \sum_{i=1}^{n}\left(6*\frac{4}{n}\right)\] \[\Large R_n = \sum_{i=1}^{n}\left(\frac{16i^2}{n^3}\right) + \sum_{i=1}^{n}\left(\frac{24}{n}\right)\] \[\Large R_n = \frac{16}{n^3}\sum_{i=1}^{n}\left(i^2\right) + \frac{24}{n}*\sum_{i=1}^{n}\left(1\right)\]

jimthompson5910 (jim_thompson5910):

now you'll use the identities \[\Large \sum_{i = 1}^{n}(i^2) = \frac{n(n+1)(2n+1)}{6}\] \[\Large \sum_{i = 1}^{n}(1) = n\]

OpenStudy (anonymous):

So then you just plug the identities into your last equation for R_n?

jimthompson5910 (jim_thompson5910):

yes then you simplify

OpenStudy (anonymous):

I got this \[\left( 32*n ^{2}+48*n+16 \right)/(6*n^2)\]

jimthompson5910 (jim_thompson5910):

this is what I'm getting (see the attached PDF)

jimthompson5910 (jim_thompson5910):

if it's too small, zoom in to at least 150%

OpenStudy (anonymous):

What the bah-jesus. You're right. Sorry, we didn't do anything like this in class and I'm incredibly confused

jimthompson5910 (jim_thompson5910):

so you're probably a lesson or two ahead?

jimthompson5910 (jim_thompson5910):

where are you stuck at?

OpenStudy (anonymous):

what I actually put for Rn and how I know when the work is done haha

jimthompson5910 (jim_thompson5910):

there is a number of different possible ways to enter Rn but one thing that I would type in, if I were doing the HW is to type in what you see on the last line (since it's the most simplified)

OpenStudy (anonymous):

Yes, that's correct! Thank you so much! How would you go about the limit as n goes to infinity?

OpenStudy (anonymous):

Actually, I figured it out! Thanks so much for your help!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!