Question

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Answer 1

familiar with derivatives ?

Answer 2

yeah

Answer 3

Good. Start by finding first and second derivatives of the given function

Answer 4

-4x^3+4x
2nd -12^2+4

Answer 5

\(f(x) = -x^4 + 2x^2\)

\(f'(x)=-4x^3+4x\)
\(f''(x)=-12^2+4\)

Answer 6

critical points occur when \(f'(x)=0\) :
\[-4x^3+4x=0\]

solve \(x\)

Answer 7

x= 0,1,-1

Answer 8

Yes, evaluate the second derivative at each of those critical values

Answer 9

ok i got 0

Answer 10

Plz Check second derivative it Should be -12x^2 + 4

Answer 11

Now just evaluate above second derivative at each point x= 0,1,-1
f''(x) = -12(x)^2 + 4

Answer 12

ok I got 0 again..