Question

NE

Answer 1

i got: 5 x cubed over 4 y to the fourth power

Answer 2

@iYuko is this right please?

Answer 3

@zepdrix

Answer 4

I can't understand the wording of your question, it's so ambiguous :(

`15 x to the eighth power over 24 y to the fifth power` divided by 4 x to the fourth power over 8 squared

So this is a fraction, divided by a fraction,
is the eight power being applied to the 15 as well? Or only the x?

Answer 5

it is 15x^8 and yes it is a fraction divided by a fraction

Answer 6

Like this?\[\large\rm \frac{15x^8}{24y^5}\div\frac{4x^4}{8^2}\]

Answer 7

exaactly

Answer 8

Recall that dividing by a fraction is the same as multiplying by the reciprocal.
So we have,\[\large\rm \frac{15x^8}{24y^5}\times\frac{8^2}{4x^4}\]

Answer 9

Let's try to cancel some stuff out.
We have 8 x's multiplying in the top,
4 x's multiplying in the bottom.

So we can divide out 4 of those x's,
leaving us with x^4 in the top, yes?

Answer 10

\[\large\rm \frac{15x^{\cancel84}}{24y^5}\times\frac{8^2}{4\cancel{x^4}}\]

Answer 11

ok!

Answer 12

\[\large\rm \frac{15x^4}{24y^5}\times\frac{8^2}{4}\]

Answer 13

i got 5x^3/4y^4 as my final answer but thats prob not right

Answer 14

@zepdrix

Answer 15

Hmm ya that seems a little off...

Answer 16

please help haha

Answer 17

Let's break up the numbers a little bit,
look for common factors.

15 is 5x3
24 is 8x3\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8^2}{4}\]

Answer 18

ah ok i see

Answer 19

You'd be much better off if you would please present your expressions in mathematical terms, and not in words. That would have avoided our going off the point in our previous discussion.

Answer 20

ok @mathmale @zepdrix is helping me already, thanks

Answer 21

lol XD

Answer 22

ok so what do we do from there? @zepdrix

Answer 23

I guess we can break down the numbers in the second fraction a little further as well,
rewrite 8^2 as 8*8,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot8}{4}\]and then rewrite that 8 as 4*2,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot4\cdot2}{4}\]And now cancel out things which appear in both the numerator and denominator.

Answer 24

Looks like the 3's will cancel out, ya?
What else?

Answer 25

yes, and the 4s

Answer 26

and the 8's, ya?

Answer 27

yup

Answer 28

So, ya, cancel your stuff,\[\large\rm \frac{5\cdot3x^4}{8\cdot3y^5}\times\frac{8\cdot4\cdot2}{4}\quad=\frac{5x^4}{y^5}\cdot\frac{2}{1}\]

Answer 29

yes!

Answer 30

an dhats all?

Answer 31

Well, multiply the 5 and 2,
but yes.

Answer 32

so, i would get : 5 x to the fourth power over 4 y cubed correct?

Answer 33

@zepdrix

Answer 34

No, you would get
10 x to the fourth power over y to the fifth power

Answer 35

but these are the only anew choices: 4 y cubed over 5 x to the fourth power
4 y to the fourth power over 5 x cubed
5 x to the fourth power over 4 y cubed
5 x cubed over 4 y to the fourth power

Answer 36

@zepdrix

Answer 37

@robtobey

Answer 38

What is the simplified form of 24 y to the fifth power over 15 x to the eighth power divided by 8 y squared over 4 x to the fourth power ?
-------------------
\[(24y^5)/(15x^8) / (8y^2)/(4x^4)\]
------
= \[(24y^5)/(15x^8)\]


= \[24y^5/8y^2] * [4x^4/15x^8\]
= \[3y^3] * (4/15x^4\]
= \[y^3 *(4/5x^4)\]
= \[(4/5)(y^3/x^4)\]

Answer 39

Hope this helped! Have a great day!

Also a medal would be much appreciated! Just click best response next to my answer. Thank You!

@iwanttogotostanford