Question

Help Please

Answer 1

To determine when the populations will be equal, set the equations equal to each other, and solve for x.
200x + 1,000 = 10(1.5x)

Answer 2

10*1.5=15

Answer 3

so it is 1200x=15x

Answer 4

explain ?

Answer 5

hint:
we can use the Taylor's expnation at first order of the exponential function at the right side, so we can write this:
\[\Large 200x + 1000 \cong 1 + \frac{{3 \cdot \ln 10}}{2}x\]

Answer 6

because first you multiply 10 by 1.5 because of dristributive property

Answer 7

so you get 15 x

Answer 8

then you add 200x+1000 to get 1200x

Answer 9

so 1200x=15x

Answer 10

The easiast solution would be 0

Answer 11

Please note that, I think that the right side is:
\[\huge {10^{1.5x}}\]
@Abdullahbasra007

Answer 12

ok

Answer 13

Thanks @Michele_Laino

Answer 14

:)

Answer 15

can you help me with one more?

Answer 16

ok!

Answer 17

1) A system of equations can be created with the two functions to determine when the populations will have the same population output value, y.
y = 200x + 1,000
y = 10(1.5x)

Answer 18

it is the same problem of above

Answer 19

ok nvm sorry