Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (chris215):

-

OpenStudy (danjs):

solve for the derivative f '(x) = 0 there it may change inc/dec or dec/inc

OpenStudy (danjs):

test each one to see if the sign changes from one side of tht point to the other

OpenStudy (chris215):

ok what I first did was find the first and second derivatives -4x^3+4x 2nd -12x^2+4

OpenStudy (mathmale):

Good. Label these derivatives. Find the three values of x that make the first derivative = to 0. Check each in the 2nd derivative. If the result is concave upward, that's where the graph changes from decreasing to increasing.

OpenStudy (mathmale):

You find the x-coordinates of the critical points by finding the 1st derivative. You use the 2nd derivative to determine whether your curve is concave up (which signifies a minimum at that x value) or down (which signifies a max). Questions?

OpenStudy (chris215):

−4x^3+4x=0 x= 0,1,-1

OpenStudy (chris215):

when I evaluate the second derivative at each of those critical values I got 0 tho

OpenStudy (mathmale):

If your second derivative is 0, that means the 2nd derivative test won't work, and that you must rely on some other method to determine how your graph is behaving.

OpenStudy (chris215):

I dont get it

OpenStudy (anonymous):

google (-x^4 + 2x^2)

OpenStudy (danjs):

inc / dec , is all they want, maximum or minimum will change from one to the other

OpenStudy (danjs):

local max/min

OpenStudy (welshfella):

can you find the derivative of -x^4 = 2x^2 ?

OpenStudy (danjs):

just test an x on eithe rside of the critical value, see if it changes in the first derivative

OpenStudy (danjs):

f'(x) will change sign - to + at a min or + to - at a max

OpenStudy (welshfella):

oh sorry you have already

OpenStudy (solomonzelman):

Other Critical Points: If f'(x) is undefined, and f(x) is defined. (Saying some point where f is not differentiable) Interval boundaries are given, then closed (the included) boundaries are also critical points. But, respectively, it is a polynomial, and no interval is given, so these two cases don't apply, but good to know for this kind of problems in general.

OpenStudy (danjs):

the second derivative about the concavirty, shows inflections

OpenStudy (danjs):

|dw:1449358986708:dw| test a value in each interval , defined by those crit values

OpenStudy (danjs):

|dw:1449359236741:dw|

OpenStudy (danjs):

increasing - decreasing - increasing - decreasing name the intervals they want, where it changes from decreasing tp increasing

OpenStudy (danjs):

general shape, for those intervals gives |dw:1449359631182:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!