Question

http://prntscr.com/9asoid

Answer 1

When are you going to stop typing? Are you writing an essay or something? @Brrandyn

Answer 2

Solve for one variable in an equation and thereafter, substitute in the other.
For instance, let us solve for x in the given system.

\[\large\ 5x-3y=-9\] Isolate the x to the other side of the equation.
\[\large\ -3y=-5x-9\]Divide -3 accordingly.

\[\large\ y=5/3x -3\]
Substitute y into the 2nd equation.
\[\large\ 2x-5y=4\]\[\large\ 2x-5(5/3x−3)=4\]
Distribute & solve for x.
\[\large\ x= ?\]
\[[\large\ ?, y]\]

Answer 3

x=2?

Answer 4

**Correction:\[\large\ y=5/3x+3\]

Answer 5

\[ \large\ 2x−5(5/3x+3)=4\]

Answer 6

How do you solve that?

Answer 7

To make it easier, convert the coefficient of the parenthesis (5) into a fraction. Multiply the fractions. After, distribute the -5 with 3 and solve using basic algebra.

\[\large\ -5=-15/3\]

Answer 8

\[\large\ 2x - ((15/3x * 5/3x) -15))=4\]

Answer 9

\[\large\ 2x -25x -15 = 4\]

\[\large\ x=?\]

Answer 10

Apply the same concept with y to solve for the solution of the system.

Answer 11

-0.8260869565

Answer 12

x=-38?

Answer 13

@IrishBoy123 is it (3,2)?