Question

given the following revenue and cost functions, find the equilibrium point to the nearest tenth. R(x)=59x-2x^2; C(x)=23x+95

Answer 1

equilibrium point would be when R(x)=C(x), or
\(59x-x^2=23x+95\)
which simplifies to
\(x^2-36x+95=0\) subject to x\(\ge\)0
however, in this case, you end up with two possible solutions.

Answer 2

Thank you! Yes i think i got it then i would plug \[2x^2-36x+95\] into the quadratic formula to get 14.8 or 3.2 as my final answer

Answer 3

Not too sure where you got the \(\color{red}{2}\) in
\(\color{red}{2}x^2−36x+95=0\)
That's where our answer differ.