Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (arihangdu):

Over the first five years of owning her car, Gina drove about 12,700 miles the first year, 15,478 miles the second year, 12,675 the third year, 11,850 the fourth year, and 13,075 the fifth year. Find the mean, median, and mode of this data.Explain which measure of central tendency will best priding how many miles she drive in sixth year.

Vocaloid (vocaloid):

well, the easiest one is mode. since all the numbers are different, there is no mode

Vocaloid (vocaloid):

to find the mean, add them all up and divide by 5

Vocaloid (vocaloid):

since there aren't any outliers, the mean is the best measure of central tendency

OpenStudy (arihangdu):

How to know this?

OpenStudy (arihangdu):

How to know this?

Vocaloid (vocaloid):

hm, it's become intuitive to me at this point but

Vocaloid (vocaloid):

an "outlier" is a data point that is very different than the others. All of the data points are similar to each other (they're all in the low 10,000 range), so we can use the mean instead of the median if there were an outlier (like, say that one of the numbers was like 50,000) then we would use the median, since the mean would be something big like 20,000 so it wouldn't be representative of the data

Vocaloid (vocaloid):

so TLDR: no outlier = use mean, outlier = use median

Vocaloid (vocaloid):

now, if you're wondering how we determine whether there's an outlier, there's a quartile test you can use but it requires a bit of calculation. for now, I would generally assume there is no outlier unless the outlier is obvious

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!