How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?

Question

anonymous · Answer

@Hayhayz

hayhayz · Answer

oh boy.. this is what I'm doing too and its confusing for me.. are you by any chance in flvs?

anonymous · Answer

Nope.

photon336 · Answer

You need to write out the balanced equation first. 

$$2C_{2}H_{6}+7O_{2} \rightarrow 4CO_{2}+6H_{2}O$$

photon336 · Answer

what this tells us is that 2 moles of ethane react with 7 moles of oxygen gas. 

we are given 62.3 grams of Oxygen so we need to convert this to moles. We do this by 

$$(\frac{ mol }{ 32grams_{oxygen gas} })*(62.3grams) =1.9468 =~ 2 moles_{oxygen gas}$$

photon336 · Answer

now that we have 2 moles of oxygen gas we need to figure out how many moles of ethane we need so we multiply this number by the molar ratio. do you know how to do this?

anonymous · Answer

no..

photon336 · Answer

We need to multiply the number of moles of oxygen gas by the molar ratio of oxygen to ethane.

$$\frac{ 2C_{2}H_{6} }{ 7O_{2} }*2mol_{Oxygen gas} = 0.57 moles, ethane$$

anonymous · Answer

That's it..?

photon336 · Answer

yes

anonymous · Answer

Thanks!

photon336 · Answer

no problem welcome to Open Study