Question

A particle of mass 0.450 kg is attached to the 100-cm mark of a meterstick of mass 0.175 kg. The meterstick rotates on the surface of a frictionless, horizontal table with an angular speed of 2.00 rad/s.
(a) Calculate the angular momentum of the system when the stick is pivoted about an axis perpendicular to the table through the 50.0-cm mark. ________________kg · m2/s

(b) Calculate the angular momentum of the system when the stick is pivoted about an axis perpendicular to the table through the 0-cm mark. ________________kg · m2/s

Answer 1

@ganeshie8
@Hero
@jim_thompson5910
@pooja195
@SolomonZelman

Answer 2

\(L = \sum I \omega\)

for a rod length L about it's centre: \(I = \dfrac{m L^2}{12} \)

for a mass m about radius r: \(I = m r^2\)

loads of situations are listed here : https://en.wikipedia.org/wiki/List_of_moments_of_inertia

for b, use parallel axis theorem, or the formula given by wiki for a rod about its end.