Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (celinegirl):

Identify the type of sequence shown in the table below and select the appropriate response. n f(n) 1 48 2 −96 3 192 4 −384 5 768 Arithmetic sequence; common difference is 96 Arithmetic sequence; common difference is −144 Geometric sequence; common ratio is 3 Geometric sequence; common ratio is −2

OpenStudy (anonymous):

so, to get from \(a_1 \rightarrow a_2\) what do you do? do you do the same thing in going from \(a_2 \rightarrow a_3\) ? if so, then you have founf the common difference or the common ratio.

OpenStudy (anonymous):

"found" not "founf"

OpenStudy (anonymous):

remember, the only 2 operations you have to consider are addition and multiplication. Hint: the sequence alternates in sign... can you get that by always adding a constant?

OpenStudy (celinegirl):

sorry for the late reply.. thanks

OpenStudy (celinegirl):

@pgpilot326 so yes its D? as said above

OpenStudy (anonymous):

@Pawanyadav please don't just give answers... the idea is for the student to learn!

OpenStudy (anonymous):

Please refer to the Code of Conduct. (below and to the left, under the posted questions section). Thanks!

OpenStudy (celinegirl):

@pgpilot326 erm not exactly.. I was understanding both of your explanations and I understood where he got D from

OpenStudy (celinegirl):

but i wasn't exactly sure if it was 100% correct

OpenStudy (anonymous):

that's okay... it's better if you provide an answer and reasoning first, rather than another providing it and you agreeing with it. i hope that makes sense.

OpenStudy (anonymous):

also, if you are done with the question, be sure to close it. Thanks!

OpenStudy (celinegirl):

@pgpilot326 well im still not sure of the correct answer so im going to keep it open or re-post it again.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!