2. For the vector W = (12, –20), determine (W) and the angle between W and the x-axis.
components 12 and -20 the tangent of the angle is y/x
is(W) supposed to be length or magnitude?
I'd be more specific and state that the horiz. comp. is 12 and that the vert. comp. is -20. I'd also suggest that you sketch this situation, and then determine which trig function is best suited to help you find the angle. You're looking for the MAGNITUDE of W.
\[\left| \left| W \right| \right|\]
In this particular case, the length is pretty much the same as the magnitude.
magnitude Im sure. that is why i need help with this problem, this is all the information i was given.
i always assume people just need the general direction to go , and get most of it and just cant get started or something.. too wordy lately
You need to determine 2 things: 1) the magnitude of the vector W, and the angle that W makes with the x-axis.
i think that is what i need help with, just getting started. Ive gone through the lesson numerous of times and examples but there is just so little information given
|dw:1449438933264:dw|
and all i have to do is find the angle between where the x axis and vector w? Im sorry, math is not my forte
|dw:1449439154154:dw| a component can be found from the difference in values from head to tail of the vector <a,b> = <(x-x1) , (y-y1)>
ok, notice the components are parallel to the axis the sides make right angles with x and y axis, you have right triangles
yes, i see
|dw:1449439393867:dw|
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