If y varies directly with x, write an equation for the direct variation. If y=6 when x=24, what is the value of x when y=7? Is the answer Y=56?
28
Can you explain how you got the answer please?
y = \[\frac{ x }{ 4 }\]
This means that 7 = x/4. Multiply each side my 4, and you get 28.
Side?
Side of the equation, with the center of the equation being the equal sign.
Do you get it now?
Ya....
@mathmale is 28 right?
Who's @mathmale
"If y=6 when x=24," write the direct proportion that applies here. In other words, find k in y=kx. Once you've done that, I can quickly check your work by substituting y=7. Better yet, start with y our own y=kx and substitute y=7. What is x?
@mathmale Aren't there infinitely many possible equations to represent this, because there is only one ordered pair given? In order for you to have one absolute equation to represent a graph, you need two or more given ordered pairs (supposing that the equation is linear).
@mathamale Is this correct? y=kx 7=ktimes8 k=8 y=8x y=7times8 y=56
@TheSmartOne
Is the equation correct?
@Mehek14 Is this equation correct? Please scroll to the bottom! :D
Is the answer y=56?
THANK YOU! :D
I believe you have the wrong answer.
I don't know what Mehek is saying, but your answer is absolutely wrong.
? @TheSmartOne
How is it wrong @TheSmartOne
It's all wrong.
All your work, all the numbers you used. They are all just wrong.
Ok no need to rub it in...But can you explain?
You need to learn how to deal with specific information first, before jumping to what you need to find. "If y varies directly with x, write an equation for the direct variation. If y=6 when x=24" Now, many people have posted this above, but can you tell me the equation for direct variation?
y=kx
ok, now here's the first part of your question: "If y varies directly with x, write an equation for the direct variation. If y=6 when x=24" Can you substitute y = 6, and x = 24 into it and solve for k?
The silence is real...
Ummmm...Can you tell me what you mean by substitute? @TheSmartOne
You're doing it all wrong @mathmale -.-
Im so confused ^_^
@mathmale You substitued the wrong numbers in and got k = 24/7 If you properly substituted it, you would have gotten 6/24 = 1/4
Borrowing TheSmartOne's input: ok, now here's the first part of your question: "If y varies directly with x, write an equation for the direct variation. If y=6 when x=24" Can you substitute y = 6, and x = 24 into it and solve for k? Direct variation implies that y=kx. If y = 6 when x=24, then 6=k(24), and k=(6/24), or 1/4. Thus, y = (1/4) x. Check! If x=24, is y=6 as it should be?
Yes or no?
Assuming that our equation of direct variation is y=(1/4)x, and now letting y=7, find x. Just substitute 7 for y in y= (1/4) x. x=?
I still can't tell whose correct
we're all on the same page now :)
@Angel360 : I went through the calculation of the value of k and then checked my own work. Next, I let y take on a different value (7 instead of 6) and substituted that into my direct variation equation. If y = (1/4)x, and y=7, find x. Please demonstrate that you can do this.
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