Inverse of a function
I already know the answer, I just want to understand it
Well the first thing we do to make this easier is replace f(x) with y.
And then you switch x and y.
Right, got it :)
\[y = 12 - \frac{ 3 }{ 4 }x~---> x = 12 - \frac{ 3 }{ 4 }y\]
And then you solve for y to isolate it again.
That's where I'm stuck, I'm not sure where to start
Well here we want to get rid of the fraction because who doesn't hate fractions. The denominator is 4 so we multiply both sides by 4.
\[x \times 4 = 12 - \frac{ 3 }{ 4 }y \times 4\]
So I have 4x = 12 - 3y?
We are multiply the entire side by 4, so the 4 will apply to ALL terms. the 4x is correct and so is the 3y, but we apply it to the 12 as well.
Okay, wasn't sure about that, alright, one sec, let me write it down
np
Alright so we have 4x = 48 - 3y so now we do what?
We move more terms. We can remove the 3 on the y. 3y is being multipled so we divide 3 on both sides.
Ack, hold on. The frist thing we had to do was subtract 12 on both sides. Woops. x = 12 - 3/4y x - 12 = -(3/4)y 4(x - 12) = -3y
I thought that was going in the wrong direction lol. no worries
So do you understand so far? Just to make sure since I made a mistake there. :x
Yes, I got it so far :)
So now we divide both sides by 3, correct?
Alright. 4(x - 12) = -3y Now we can pass on the -3. We divide it on both sides.
Yes. =)
Sweet, you got me to the right answer. I appreciate it :)
It would be -4/3(x - 12) If you want to avoid confusion you can just multiply the inverse. From (-3/4)y you can change it to -4/3 and attach it to the x. SAme exact thing, less confusion. Dividing a fraction is the same and multiply by its inverse!
Np, also make sure that you use \[f^{-1}(x)\] to replace the y we changed at the beginning
to indicate :)
Right, I'm just practicing stuff so I can get better at math, thanks again for helping so much :)
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