Help with logs
I'm not sure how to plug in the numbers, even in Mathway I couldn't get it to work
Use logarithmic rules to pull apart each expression. For a) use the sum and difference rules of logs to pull apart the expression into ln(a^-2)-ln(b)-ln(c). Then use the power rule to pull out the exponent. -2ln(a)-ln(b)-ln(c). Now you can plug in the values given for ln(a), ln(b), and ln(c). It will be -2(2)-3-5 which is -12. Try this for the rest of the problems.
Ohh I see! I'll try that
\[\ln a^m=m lna\] for example \[\ln \sqrt{b^2c^{-3}a^{-4}}=\frac{ 1 }{ 2 } \ln b^2c^{-3}a^{-4}=\\\frac{ 1 }{ 2 }( \ln b^2+\ln c^{-3}+\ln a^{-4})=\\\frac{ 1 }{ 2 } (2\ln b-3lnc-4lna)\]
Is part b -6.5?
Sorry, it's -8.5?
Part C is 5.67?
Yes -8.5 is correct.
Part D is a little confusing, is it -10?
I got Part C and D wrong I'll try again
I need help with Part C and D
Part C is either (lna+3lnb)*(lnb+lnc)^2 or (lna+3lnb)/(-2(lnb+lnc)). I'm not sure exactly what part of the expression the -2 exponent belongs to. Part C is either 704 or -.6875. Part D is -2lnc*(lna-lnb)^3 which is +10 because it is the same as (-10)*(-1)^3.
The trick here is to apply rules of logs before substituting in the given values for log a, log b, log c, and so on. Part D involves multiplication. What is the log of E * F, in terms of log E and log F? What is\[\ln c ^{-2}\]
in terms of ln c?
Which rule of logs applies to division? How would you simplify \[\ln \frac{ P }{ Q }?\]
Hope this helps you to get back on track.
.04?
I've asked a lot of questions. Which one were you answering here?
The lnc^-2
Actually, Brandon, I'd wanted y ou to use rules of logs FIRST, and only after having simplified ln c^(-2) as far as possible, substitute ln c = 5. Mind doing that now? Using rules of logs, simplify ln c^(-2)
Brandon?
I am having a little trouble, most of this is new to me
do you have access to a list of rules of logarithms? If not, good idea to make one up. You are to simplify \[\ln c ^{-2}\]
The rule for simplifying powers of c is as follows:
\[\ln c^d=d*\ln c\]
Following this rule, simplify:\[\ln c ^{-2}\]
Brandon, what's the value of "d" in this problem?
-2?
-2 * lnc
That's right! Now, go back to the original problem. It tells us that ln c is what? Please write ln c, not lnc. ln c = ?
5
Right. Therefore, \[\ln c ^{-2},when \ln.c=5, is -2 (5)=?\]
-10
oh so it is not 5^-2
That's a part that was confusing me
-10 is correct. 5^-2 is not.
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