Suppose the integral from 2 to 6 of g of x, dx equals 12 and the integral from 5 to 6 of g of x, dx equals negative 3, find the value of the integral from 2 to 5 of 3 times g of x, dx .

Question

Suppose the integral from 2 to 6 of g of x, dx equals 12 and the integral from 5 to 6 of g of x, dx equals negative 3, find the value of  the integral from 2 to 5 of 3 times g of x, dx .

anonymous · Answer

https://gyazo.com/d93ca0e3dc7d22cf4cb98fb0d12da039

anonymous · Answer

@jim_thompson5910 Would it not be -9?

caozeyuan · Answer

Should be -9, I am really confused

anonymous · Answer

Same
Unless there's another method

tkhunny · Answer

I can't read your link.  Recommendation: Learn a little LaTeX and give it a good show.

Generally, 
$\int\limits^{6}_{2}g(x)\;dx = \int\limits^{5}_{2}g(x)\;dx + \int\limits^{6}_{5}g(x)\;dx$

anonymous · Answer

@tkhunny that is not what they ask for. They have $$\int\limits_{2}^{6}g(x)= 12 and \int\limits_{5}^{6}g(x)=-3      what is   \int\limits_{5}^{6}3g(x)$$

jim_thompson5910 · Answer

@Ephemera you wrote `find the value of  the integral from 2 to 5 of 3 times g of x, dx .` for the third integral

but the third integral shown in the link is $$\Large \int_{5}^{6}3g(x)dx$$

anonymous · Answer

That's weird I copied and pasted the question and it seems the pictures translated into text. So there must be an error in the photo.

anonymous · Answer

Thanks for pointing that out.

jim_thompson5910 · Answer

yeah I'm guessing they meant to write $$\Large \int_{2}^{5}3g(x)dx$$

anonymous · Answer

I got 45

jim_thompson5910 · Answer

use the equation @tkhunny wrote out and you can isolate $$\Large \int_{2}^{5}3g(x)dx$$think of it as a variable

anonymous · Answer

That's what was done. Got 15 for 2 to 5 then multiplied by 3 to get 45

jim_thompson5910 · Answer

oh sorry, without the 3, but yeah the final answer will be 45

anonymous · Answer

Mind helping with another? This one really has me puzzled.

jim_thompson5910 · Answer

sure