Question

how to graph sin x > cos x? and sin x < cosx?

Answer 1

I think the objective is to determine the interval or intervla on which sin x > cos x.

Graph both sin x and cos x on the same set of axes. Mark them (sin x, cos x). It should be obvious where sin x > cos x. Identify the interval(s) on which this inequality is true.

Answer 2

i still dont get it..

Answer 3

http://www.wolframalpha.com/input/?i=y+%3D+cos+x%3B+y+%3D+sin+x

Answer 4

Look at the graphs of sin x and cos x in the link above.

Answer 5

Let's look at the first inequality, \(\sin(x)>\cos(x)\). If we plot the lines \(\sin(x)\) and \(\cos(x)\) on a graph we get this graph. The red line is \(y=\sin(x)\) and the blue is \(y=\cos(x)\). We want to find the values of \(\sin(x)>\cos(x)\), so where is the red line above the blue line?

Answer 6

the sin x is in the same spot?

Answer 7

I don't understand what you're asking. Can you see where the red line is above the blue line?

Answer 8

i think so.
the link you sent is sin x = cos x?

Answer 9

im really confused on how to draw sin x > cos x and <

Answer 10

No, the link I sent is plotting y=sin(x) in red and y=cos(x) in blue. Can you see that the red line is above the blue line between points A and B in this graph:

https://i.imgur.com/FFcxDv8.png

Answer 11

ok yes i see that

Answer 12

Do you know how to graph inequalities?

Answer 13

i dont remember

Answer 14

do i need to shade something for the inequalities?

Answer 15

Read this: http://www.purplemath.com/modules/ineqgrph.htm

The region between \(A\) and \(B\), where \(sin(x)>cos(x)\) is what we need to shade. I can't work out how to plot this nicely for you so I'll draw it: