Question

I have no idea what I'm doing wrong! Please help!

Answer 1

if that picture is not clear enough, i can take another...

Answer 2

unless (dv - v)/dt is equal to a, then im probably doing it wrong ><

Answer 3

This picture might be slightly clearer

Answer 4

How does the textbook find the formula for velocity, just curious

Answer 5

the same way i have it on my sheet.

Just assume x'=y*(x-ut) and t'=y*(t-ux/c^2) is a given.

Answer 6

From that you can find dx' and dt' like i did on my sheet (which is the same way the textbook did it) i can post the textbook pictures if you would like, but its honestly the same lol

Answer 7

i know everything is correct up till v'=(vx-u)/(1-uv/c^2), as these were all given in the text... its just after v'=(vx-u)/(1-uv/c^2) im not entirely sure if im doing it correctly.

Answer 8

I kinda have to sleep cause i have class early tomorrow and two exams within the next week >.< ill prolly be back in 6 hours or so?

Sorry :s

Answer 9

So i figured it out lol...turns out i forgot to take the derivative of the constants (which is 0)
i feel so dumb -.-