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\[\sin \frac{ 5\pi }{ 8 }\]
Use the sin half angle identity. sin(x/2)=\[\sqrt{(1-cosx)/2}\] If x/2=5π/8 then x=5π/4 Plug this into the half angle identity to get \[\sqrt{(1-cos(5π/4))/2}\] This simplifies to \[\sqrt{(2-√2)/4}\] and then into √(2-√2)/2
Just to clarify, the negative square root is discarded because 5π/8 is in Q2 so sinx has to be positive.
thanks so much!
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