Graphing transformations, how is the f function affected?. question. y = - 2f (x+1) +1
Okay, it moves 1 unit to the left for x unit (subtract 1) and up one y-unit (add 1). What does the -2 in front of the f function do?
The 2 is a scaling factor, it doubles the output, so the function is stretched vertically by a factor of 2. The negative reflects the function across the x-axis.
@zepdrix so doing it algebraically, I would multiply the y unit by 2?
You mean to get your new y value from the previous f? You would do these transformations, `in this order`: Shift it 1 left, Reflect it across the x-axis, Multiply it by 2, Shift it 1 up The reason I'm making a point about the order is because notice that the negative sign is not being applied to the +1 on the end.
So shift 1 x-unit left, shift 1 y-unit up, and multiply 2 to what? both x and y?
to get the new function
this is for when I am plotting points for the new function
Ahh sorry. Shift 1 left (Decrease x by 1) Reflect it across the x-axis (y value becomes negative) Multiply by 2 (Multiply y value by 2) Shift 1 up (Increase y by 1) Every transformation is applied to y, except for the left/right shift. Let's take one arbitrary point, such as (2,5). Shift 1 left (1,5) Reflect (1,-5) Multiply by 2 (1,-10) Shift 1 up (1,-9) We started at (2,5) and our transformation took us to (1,-9).
Okay, I see it not with your explanation. Graphing is my weakest area, so I'm reviewing graphing concepts. Thanks! :)
not=now*
np!
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