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Mathematics 21 Online
OpenStudy (anonymous):

Can anybody teach ,e how to do slope intercept equations ?

OpenStudy (anonymous):

do you mean when you say slope y=mx+b ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

y = mx + b This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept.

OpenStudy (anonymous):

\[y=mx+b\]where\[y=vertical~axis\]\[x=horizontal~axis\]\[m=slope\]\[b=y-intercept\]

OpenStudy (anonymous):

For example, Find the equation of the straight line that has slope m = 4 and passes through the point (–1, –6).

OpenStudy (anonymous):

Thanks !

OpenStudy (anonymous):

Okay, they've given me the value of the slope; in this case, m = 4. Also, in giving me a point on the line, they have given me an x-value and a y-value for this line: x = –1 and y = –6.

OpenStudy (anonymous):

Thanks !

OpenStudy (anonymous):

In the slope-intercept form of a straight line, I have y, m, x, and b. So the only thing I don't have so far is a value for is b (which gives me the y-intercept). Then all I need to do is plug in what they gave me for the slope and the x and y from this particular point, and then solve for b:

OpenStudy (anonymous):

y = mx + b (–6) = (4)(–1) + b –6 = –4 + b –2 = b Then the line equation must be "y = 4x – 2"

OpenStudy (anonymous):

Yw! @breezy34362 Btw,\[\huge{Welcome~To~Openstudy}\] @breezy34362 :)

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