Question

Please check my work :)

Question:
How many milliliters of calcium, with a density of 1.55 g/mL, are needed to produce 98.5 grams of calcium hydroxide in the single-replacement reaction below? Show all steps of your calculation as well as the final answer.

Ca + H2O → Ca(OH)2 + H2

My Answer:
Balanced Equation: Ca + 2 H2O → Ca(OH)2 + H2
The Math: 98.5 g Ca(OH)2 over 74.0932 g/mol times (1 over 1) times 40.0784 g/mol over 1.55 g/mL = 34.4 mL Calcium.

Answer 1

That looks right to me. :P

Answer 2

Cool, tysm! :)

Answer 3

Welcome. :3