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Mathematics 21 Online
OpenStudy (benlindquist):

Graphs

OpenStudy (benlindquist):

OpenStudy (benlindquist):

(x + 4, y + 3) (x + 3, y + 4) (x - 3, y - 4) (x - 4, y - 3

OpenStudy (benlindquist):

How would you figure this out?

OpenStudy (igreen):

T = (-3, -2) T' = (0, 2)

OpenStudy (igreen):

Find out what you have to add/subtract to -3 to get 0, and what you have to add/subtract from -2 to get 2.

OpenStudy (benlindquist):

Would it be (x - 3, y - 4)

OpenStudy (anonymous):

yes

OpenStudy (benlindquist):

ok

OpenStudy (igreen):

No, -3 - 3 does not equal 0

OpenStudy (igreen):

It equals -6

OpenStudy (benlindquist):

Cause you add them

OpenStudy (igreen):

And -2 - 4 is -6, not 0

OpenStudy (igreen):

not 2*

OpenStudy (anonymous):

no -3 and 3 is 0

OpenStudy (benlindquist):

You are seeing -3 and 3 don't you add them?

OpenStudy (igreen):

Yes, you add 3 to -3 to get 0.

OpenStudy (igreen):

So you add 3 to the x. \(\sf (x + 3,~?)\)

OpenStudy (igreen):

Now what do you add or subtract from -2 to get 2?

OpenStudy (benlindquist):

Subtract?

OpenStudy (igreen):

-2 + x = 2 Can you solve that for 'x'?

OpenStudy (benlindquist):

it would be 0

OpenStudy (igreen):

No..how did you get that? Add 2 to both sides.

OpenStudy (benlindquist):

So 2 + x = 4

OpenStudy (benlindquist):

(x - 4, y - 3)

OpenStudy (igreen):

-2 + 2 doesn't equal 2

OpenStudy (benlindquist):

weird its 0

OpenStudy (igreen):

Yes, so that gives us: x = 4

OpenStudy (igreen):

So we ADD 4 to the y-value, giving us: \(\sf (x + 3, x + 4)\)

OpenStudy (igreen):

\(\sf y + 4*\)

OpenStudy (benlindquist):

so the answer would be (x + 4, y + 3)

OpenStudy (igreen):

No, it's the other way around. \(\sf (x + 3, y + 4\)

OpenStudy (benlindquist):

ok

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