Mathematics
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OpenStudy (benlindquist):
Graphs
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OpenStudy (benlindquist):
OpenStudy (benlindquist):
(x + 4, y + 3)
(x + 3, y + 4)
(x - 3, y - 4)
(x - 4, y - 3
OpenStudy (benlindquist):
How would you figure this out?
OpenStudy (igreen):
T = (-3, -2)
T' = (0, 2)
OpenStudy (igreen):
Find out what you have to add/subtract to -3 to get 0, and what you have to add/subtract from -2 to get 2.
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OpenStudy (benlindquist):
Would it be (x - 3, y - 4)
OpenStudy (anonymous):
yes
OpenStudy (benlindquist):
ok
OpenStudy (igreen):
No, -3 - 3 does not equal 0
OpenStudy (igreen):
It equals -6
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OpenStudy (benlindquist):
Cause you add them
OpenStudy (igreen):
And -2 - 4 is -6, not 0
OpenStudy (igreen):
not 2*
OpenStudy (anonymous):
no -3 and 3 is 0
OpenStudy (benlindquist):
You are seeing -3 and 3 don't you add them?
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OpenStudy (igreen):
Yes, you add 3 to -3 to get 0.
OpenStudy (igreen):
So you add 3 to the x.
\(\sf (x + 3,~?)\)
OpenStudy (igreen):
Now what do you add or subtract from -2 to get 2?
OpenStudy (benlindquist):
Subtract?
OpenStudy (igreen):
-2 + x = 2
Can you solve that for 'x'?
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OpenStudy (benlindquist):
it would be 0
OpenStudy (igreen):
No..how did you get that?
Add 2 to both sides.
OpenStudy (benlindquist):
So 2 + x = 4
OpenStudy (benlindquist):
(x - 4, y - 3)
OpenStudy (igreen):
-2 + 2 doesn't equal 2
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OpenStudy (benlindquist):
weird its 0
OpenStudy (igreen):
Yes, so that gives us:
x = 4
OpenStudy (igreen):
So we ADD 4 to the y-value, giving us:
\(\sf (x + 3, x + 4)\)
OpenStudy (igreen):
\(\sf y + 4*\)
OpenStudy (benlindquist):
so the answer would be (x + 4, y + 3)
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OpenStudy (igreen):
No, it's the other way around.
\(\sf (x + 3, y + 4\)
OpenStudy (benlindquist):
ok