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,MEDAL GIVEN!!! A couple plans to have four children. Using a tree diagram , obtain the sample space. Then, find the probability that the family has no boys
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Using the tree, we get the sample space: {b,b,b,b} {b,b,b,g} {b,b,g,b} {b,b,g,g} {b,g,b,b} {b,g,b,g} {b,g,g,b} {b,g,g,g} {g,b,b,b} {g,b,b,g} {g,b,g,b} {g,b,g,g} {g,g,b,b} {g,g,b,g} {g,g,g,b} {g,g,g,g} So for instance {b,g,g,b} means that the couple had a boy, girl, girl, and then a boy (in that order). Note: recall, the sample space is the set of ALL possible outcomes.
So the probability of the couple having AT LEAST 3 boys is 5/16 which is 0.3125 in decimal form which gives a 31.25% chance.
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