can someone help me? i need like a walk through. im willing to do work, i just dont understand
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OpenStudy (maddisongruby):
this is the problem
OpenStudy (anonymous):
Do you know what vertex form looks like?
OpenStudy (maddisongruby):
isnt it y= a(x-h)^2 ? @q12157
OpenStudy (anonymous):
y= a(x-h)^2+k where k is just any constant
OpenStudy (anonymous):
luckily you dont have any constants in front of the x^2, so you can go straight into completing the square :p
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OpenStudy (anonymous):
Do you know how to complete the square?
OpenStudy (maddisongruby):
no, but isnt it like factoring?
OpenStudy (maddisongruby):
but 20 is k right?
OpenStudy (anonymous):
sorta. basically the goal of completing the square is to get it into a (x-h)^2 state.
OpenStudy (anonymous):
So in our problem y=x^2-12+20
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OpenStudy (anonymous):
er y=x^2-12x+20
OpenStudy (anonymous):
what you do when you complete the square is you take the constant in front of x
OpenStudy (anonymous):
which is?
OpenStudy (maddisongruby):
12
OpenStudy (anonymous):
-12 dont forget the negative sign
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OpenStudy (anonymous):
and then you divide it by 2
to get?
OpenStudy (maddisongruby):
6
OpenStudy (anonymous):
and then you square it to get?
OpenStudy (maddisongruby):
36
OpenStudy (anonymous):
so what you want to do now is you have your equation:
y=x^2-12+20
and you want to add 36 and then subtract 36.
This is so that you get:
y=x^2-12+36+20-36
This is still the same equation as before right?
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OpenStudy (maddisongruby):
yep! and we end up with...... y= (x-6)^2+20? i think
OpenStudy (anonymous):
y=x^2-12x+20 and y=x^2-12x+36+20-36 Sorry for the mistypes
OpenStudy (anonymous):
close remember how we also subtracted a 36
OpenStudy (anonymous):
so you need to do 20-36 as well
OpenStudy (anonymous):
so what is your final answer?
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OpenStudy (maddisongruby):
oooo so y= (x-6)^2-16?
OpenStudy (anonymous):
Yep!!
OpenStudy (anonymous):
and that is in vertex form, so to answer your question from before, k=/=20 but instead -16
OpenStudy (maddisongruby):
okay, i get it! can you help me with one more?
OpenStudy (anonymous):
mhm sure lol
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OpenStudy (maddisongruby):
OpenStudy (maddisongruby):
i know its like slope, but its a different formula i think
OpenStudy (anonymous):
Oh this isnt so bad. I'm assuming average rate of change is constant from the two points.
OpenStudy (anonymous):
Basically what you need to do is plug in those two points into the function g(x)
OpenStudy (maddisongruby):
okay let me do that
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OpenStudy (anonymous):
so then you have two x points and two y points.
Then you use the slope formula
OpenStudy (anonymous):
So your two points should be?
OpenStudy (maddisongruby):
15 and 33 are what i got when i plugged them in
OpenStudy (maddisongruby):
and 3 is the y intercept i think so is that part of the points?
OpenStudy (anonymous):
(4, 15) and (6, 33) yep!
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OpenStudy (maddisongruby):
oooo okay never mind that last thing
OpenStudy (anonymous):
whenever you see rate of change, it just means slope. Rate of change = slope. So y intercept is unnecessary.
Now you have your two points you can just find slope lol
OpenStudy (maddisongruby):
so y2-y1/x2-x1?
OpenStudy (anonymous):
yep
OpenStudy (maddisongruby):
is the rate of change 9? @q12157
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