If an object is dropped from a height, its downward speed theoretically increases linearly over time because the object is subject to the steady pull of gravity. Here are observational data on the speed of a ball dropped from a certain height at time x = 0: Time (seconds) X 0 0.2 0.4 0.6 0.8 Speed (m/sec) Y 0 1.92 3.58 6.01 7.88
Let me graph it real fast and see if I can determine a correlation.
Ok, thanks for helping me AlycaT
K well here is the graph.
I do believe for this we will have to do the standard deviation again like we did once before with the trillions of steps.
We can tell though that the correlation is positive.
ok awesome, are you cool with helping me with the billion steps again
Yes if you would like me to. :)
We can use this as a guide again.
So first thing to do is get all of your x-values and find the average, then do the same with the y's.
The average of the x's is .4 The average of the y's is 3.882
Your next step is to subtract .4 from every x-value and to subtract 3.882 from every y-value..
ok give me one second plz
x-values 0 - .4 = -.4 .2 - .4 = -.2 .4 - .4 = 0 .6 - .4 = .2 .8 - .4 = .4 y-values 0 - 3.882 = -3.882 1.92 - 3.882 = -1.962 3.58 - 3.882 = -.302 6.01 - 3.882 = 2.128 7.88 - 3.882 = 3.998
i got all of those for z the same
*x I mean
Your next step is to multiply your x-values by your y-values.. -.4 (-3.882) = 1.5528 -.2 (-1.962) = .3924 0 (-.302) = 0 .2 (2.128) = .4256 .4 (3.998) = 1.5992
i got the same y's
Now you square your x's and y's.. x-values -.4 squared = .16 -.2 squared = .04 0 squared = 0 .2 squared = .04 .4 squared = .16 y-values -3.882 squared = 15.069924 -1.962 squared = 3.849444 -.302 squared = .091204 2.128 squared = 4.528384 3.998 squared = 15.984004
then you add them i think???
Now add up your the x(y)'s the x-squared's and the y-squared's The x(y)'s added up is = 3.97 The x-squared's added up is = .4 The y-squared's added up is = 39.52296
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