Question

A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

this is just like the other one we solved

Answer 2

do you remember where to start?

Answer 3

the molar mass of glucose is 180

Answer 4

@Vocaloid

Answer 5

@Vocaloid

Answer 6

good, now convert 25.5g to moles...

Answer 7

0.14

Answer 8

@Vocaloid

Answer 9

now convert the mass of water to kg

Answer 10

0.398

Answer 11

good, now find molality

molality = moles/kg = ?

Answer 12

0.35?

Answer 13

@Vocaloid

Answer 14

good now use the formula

mKi

where m = molality, K = freezing point constant, and i = 1

Answer 15

-0.65