A solution is made by dissolving 3.8 moles of sodium chloride (NaCl) in 185 grams of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.
@Vocaloid
same process as before... i = 2 k = your constant m = molality = moles/kg
can you go through it again
@Vocaloid
what first?
follow the steps http://openstudy.com/users/tywower#/updates/5666086de4b07e0ce13777b0
molar mass of nacl is 58.4
0.185 kg of water
20.54 is the molality, 0.51 is the constant
10.47 is the boiling point?
@Vocaloid
actually there's one more step
since the boiling point of water is 100C, just add 100 to the number you just got
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