Question

urgent FAN AND MEDAL a country's population in 1991 was 147 million. In 1998 it was 153 million what's the population in 2017

Answer 1

are you supposed to use exponential growth as in \[P(t)=P_0e^{rt}\]?

Answer 2

or can you do something easier?

Answer 3

its like P=Ae^kt

Answer 4

we can do it that way if you like
take a bit of time

Answer 5

sure

Answer 6

we can also do it a quick way using just the numbers given
lets to it that way first

Answer 7

alright

Answer 8

in 7 year (from 1991 to 1998) it went from 147 to 153
you can model it as \[P(t)=147\times \left(\frac{153}{147}\right)^{\frac{t}{7}}\]

Answer 9

then if you want to know what it is 26 years later, from 1991 to 2017 replace \(t\) by \(26\) and get this
http://www.wolframalpha.com/input/?i=147%28153%2F147%29^%2826%2F7%29

Answer 10

would you like to do it the slow way now?

Answer 11

set it up as \[P=Ae^{kt}\] and find \(k\) ?

Answer 12

you might have to do it on a test or sommat, i don't know
it is up to you

Answer 13

since its timed i might use wolfram i just dont know how to enter the problem into it

Answer 14

thats y i didnt use it before

Answer 15

you can use the link i sent

Answer 16

otherwise we have to set \[153=147e^{9k}\] and solve for \(k\)
then make the equation and evaluate at \(t=26\)

Answer 17

Substitute the original population and the model becomes \[P = 147e^{kt}\]
7 years later the population becomes 153. Substitute P with 153. \[153 = 147e^{7k}\]
Now solve for k. \[153 = 147e^{7k}\] and t = 16

Answer 18

that is the second way
do you know how to solve \[153=147e^{7k}\] for \(k\)?

Answer 19

no

Answer 20

do you want to know or are you satisfied with the answer above?