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Chemistry 19 Online
OpenStudy (anonymous):

please help I collected this data at the end of a titration lab. what is the concentration of the acid ? show work. this was the data I collected 0.20 molar NaOH 30 ml NaOH 45 mL HCI

OpenStudy (ramirocruzo):

You can find it out like this: NaOH + HCl => NaCl + H2O 0.20 M 30 ml NaCl has 0.20x30x10^-3 moles=0.06 moles.... That means 0.06 moles of HCl were also involved...... So.... \[M=\frac{ No. of moles }{ Volume [ ltr ]}\]

OpenStudy (ramirocruzo):

Which would come up to be....0.166 M

OpenStudy (anonymous):

omg thank you so much

OpenStudy (ramirocruzo):

Anytime.....:D

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