okay so i have 2 questions pertaining to stoichiometry, is anyone willing to help. i will fan and medal
@escamer are you good with chem?
im sorry but i dont know this ;-;
its cool, but thanks for looking
np :)
Ok, so first, do you know the order of conversions?
no im not familiar with that, i just started this class @snackshack79
alright, I'm fairly new to this too. the order of conversions is going to be grams > moles > moles > grams
okay so like i have to turn grams to moles, and back?
real quick, how much do you already understand? do you understand the cross cancellation that has to take place?
yeah, i know that, and i know i have to make the chart. i also know Tripotassium phosphate (K3PO4) has a Molar mass approx: 212.27 g/mol
well lets focus on the first one first
do you know what to start with?
okay so for that one, i need to make the chart that looks like this right?|dw:1449600517184:dw|
well, I Learned it a bit differently first your going to need to start with 42.0 g Na2O
and thats the molar mass?
so do you know how to convert it to moles?
yes. i can convert to moles
alright, how?
42 g Na2O x (1 mol Na2O / 62 g) = 0.6774 mol Na2O, 62 is the molar mass, of the compound
this is where i got stuck
alright, that looks good so far, but there's going to be more to the equation. next we need to convert from moles of sodium oxide to moles of sodium
so this step is going to be (x mol Na / y mol Na2O)
do you know what x and y are going to be?
y is gonna be 0.6774 mol Na2O right?
nope, the x and y values are both in your balanced equation
4 and 2?
exactly!!!
and we multiply by the .6774?
so, so far we have: 42 g Na2O x (1 mol Na2O / 62 g) (x mol Na / y mol Na2O) we are going to need to multiply in one more of these fractions, and then we'll be done
oops, sorry, I meant: 42 g Na2O x (1 mol Na2O / 62 g) (4 mol Na / 2 mol Na2O) so, now we're going to convert it back to grams, this time grams of sodium (Na)
0.6774 mol Na2O x (4 mol Na / 2 mol Na2O) = 1.3548 mol Na, i think
and that 1.3548 mole is 31.16 grams of Na
alright, that looks good, but I'm going to need to see that last step between moles of Na and grams of Na
31.16 grams of sodium?
alright, what is the fraction you used to get 31.16?
do you want me to be honest? i just put 1.3548 mol converted to grams in google
alright, that's fine, but your going to need to know this conversion: x g Na / 1 mol Na
any idea what replaces the x?
so 42g Na/ 1 mol Na?
no, for any conversion between grams and moles, there will be 1 mol, and the grams will be the molar mass of the molcule
ohhhh so......23 g?
yep, so can we put the whole equation together, so we can solve the whole thing?
this is what i got on my paper, convert the 42 g of Na2O into mol. 42 g Na2O x (1 mol Na2O / 62 g) = 0.6774 mol Na2O how many mol Na are needed to produce 0.6774 mol Na2O. 0.6774 mol Na2O x (4 mol Na / 2 mol Na2O) = 1.3548 mol Na convert the mol Na into grams. 1.3548 mol Na x (23g Na / 1 mol Na) = 31.16 grams Na therefore, 31.16 grams of Na are needed to produce 42.0 grams of Na2O. is this correct?
Perfect!!!
so can you help me as i go through the last one?
sure
wait! i just found something in my note book! 1 mole K2PO4 yields 3 moles KNO3
that's what the balanced equation is saying too
this one's easy, its just mole to mole
so do i multiply that ratio by 2.5 to get my answer?
pretty much, but can you tell me the equation you're supposed to use?
ummm 2.5mol of Potassium phosphate (1 mole K3PO4/ 3 moles KNO3)
and you get 7.5 mol?
not quite, you got the right answer, but your fraction's upside down
so what should it look like?
2.5 mol K3PO4 ( 3 moles KNO3 / 1 mole K3PO4)
ohhh okay, thank you so much! and i may definitely be needing your help in the future
alright, if I'm on I'll certainly help you if you tag me
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