Question

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Answer 1

hint: the acceleration is the derivative of the velocity

know where to go from here?

Answer 2

not really

Answer 3

take the derivative of v(t) = 3t^2 - 4t + 1,

Answer 4

oh ok I got v'(t)=6t-4

Answer 5

yes, the instantaneous velocity at any time, use t=3

Answer 6

ok do I plugg that into v'(t)=6t-4?

Answer 7

The derivative is the rate of change , with respect to time here

rate of change of Distance km ... velocity km/s

rate of velocity change ......acceleration km/s^2

Answer 8

yes,

a(t) = v ' (t) = 6t - 4

Answer 9

ok i got 14

Answer 10

14 ft/s^2 thanks for the help!!

Answer 11

welcome