Question

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Answer 1

remember velocity and accelerations are time derivatives of the position function

s(t)
v(t) = d/dt [ s(t) ]
a(t) = d/dt [ s(t) ] = d^2/ dt^2 [ s(t) ]

Answer 2

you can use the chain rule on that one s(t)

v(t) = s ' (t ) = t * (1/5t) *5 + ln(5t) * 1 = 1 + ln(5t)

Answer 3

take derivative of that velocity to get accel a(t) you ned

Answer 4

I got 1/t?

Answer 5

should be 1/(5t)

Answer 6

the only answer choice I have is 5e or 5e^2

Answer 7

it is 5e

Answer 8

didn't saw v=0 there