Question

could someone help me with some algebra 2 problems?

Answer 1

yes

Answer 2

please post your question

Answer 3

@MD152727

Answer 4

First. Factor \[3x^2-17x-6\] by find factors of \[3(-6)\] whose sum is -17. This gives you: \[\frac{4x^2-32x+48}{x(3x+1)-6(3x+1)}\] Factor common terms:\[\frac{4x^2-32x+48}{(3x+1)(x-6)}\] Now factor out the greatest common divisor, at the numernator: \[\frac{4(x^2-8x+12)}{(3x+1)(x-6)}\] Now factor it:\[\frac{4(x-2)(x-6)}{(3x+1)(x-6)}\] Now cancel the terms: \[\frac{4(x-2)}{3x+1}\]

Answer 5

Hope it makes sense @coltonbasham

Answer 6

I am still confused on what my answer would be i see the work and understand that but i dont know

Answer 7

@Tommynaiter

Answer 8

http://openstudy.com/study#/updates/56675e98e4b0683b3e9c8724

Answer 9

You answer is \[\frac{4(x-2)}{3x+1}\] Which is one of your options :) ?

Answer 10

@Tommynaiter could you help wit another one

Answer 11

@Hero could you help me

Answer 12

do you still need help?

Answer 13

4