Mathematics
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OpenStudy (anonymous):
Please help with 4 questions
ASAP medal+fan
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OpenStudy (anonymous):
OpenStudy (anonymous):
2-5
OpenStudy (anonymous):
@mathmate @mathmale
OpenStudy (anonymous):
2-5
OpenStudy (anonymous):
Please help
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OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
@mathmate @mathwiz916 @mathmale @mathwizzard3 @MathematicalyExactOne
OpenStudy (anonymous):
@mathmale
OpenStudy (anonymous):
Can you please help
OpenStudy (anonymous):
2-5 on this attachment
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OpenStudy (anonymous):
please help for fan and medal
OpenStudy (anonymous):
someone help!
OpenStudy (anonymous):
i am so confused i have been working for 3 hours and got 1 problem done
OpenStudy (amy0799):
ok, I think I know how to do this.
Can you tell me what the area of a circle is? and the circumference of a circle is?
OpenStudy (anonymous):
a=pi times r
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OpenStudy (anonymous):
c=2pi times r
OpenStudy (amy0799):
you forgot the squared for area.
A=pi(r)^2
OpenStudy (amy0799):
for the first problem, you want to set the given circumference to the equation, 2pi(r)
352=2pi(r)
OpenStudy (anonymous):
oh yeah
OpenStudy (anonymous):
i got 9859
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OpenStudy (anonymous):
but for 2-5 i didn't get
OpenStudy (amy0799):
It's basically the same set up.
For 2, 3 1/7 = pi(r)^2, solve for r, and plug it into the C=2pi(r)
OpenStudy (anonymous):
what did you get
OpenStudy (amy0799):
i got C=1.0272
OpenStudy (anonymous):
Same
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OpenStudy (anonymous):
Let's do number 3
OpenStudy (anonymous):
wait what did you get for number 1 i got 9859
OpenStudy (anonymous):
is that what you got?
OpenStudy (amy0799):
i got 9856
OpenStudy (anonymous):
that's what i got the first time
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OpenStudy (amy0799):
that's due to rounding probably, i used 22/7 for pi
OpenStudy (anonymous):
what did you get for number 3
OpenStudy (amy0799):
did you already solve for it?
OpenStudy (anonymous):
not yet i'm about to
OpenStudy (amy0799):
i got my answer, tell me yours first
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OpenStudy (anonymous):
i don't get this one
OpenStudy (anonymous):
i got something really off so i don't really want to say it
OpenStudy (anonymous):
how do i solve this
OpenStudy (amy0799):
the set up is exactly the same as question 2
15,400=2pi(r), solve for r and plug into C=2pi(r)
OpenStudy (anonymous):
how do you solve for r
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OpenStudy (amy0799):
oops, that should be pi(r^2), because it's squared, you need to take the square root of it
so \[\sqrt{15,400/22/7}\]
OpenStudy (anonymous):
i don't get this
OpenStudy (amy0799):
first solve for 15,400/2pi, what do you get? use 22/7 for pi
OpenStudy (amy0799):
i keep messing up, sorry, 15,400/pi
OpenStudy (anonymous):
i got this
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OpenStudy (amy0799):
that's because you divided it the other way around
divide 15,400 by 22/7
15,400/(22/7)
OpenStudy (anonymous):
100
OpenStudy (amy0799):
plug what i have typed exactly, with the parenthesis
OpenStudy (anonymous):
4900
OpenStudy (amy0799):
good, now you need to square root it
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OpenStudy (anonymous):
24010000
OpenStudy (amy0799):
that's squaring it
square root is \[\sqrt{4900}\]
OpenStudy (anonymous):
how do you square root it
OpenStudy (amy0799):
do you have a calculator?
OpenStudy (anonymous):
yes
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OpenStudy (amy0799):
is it Texas Instruments TI-30X?
OpenStudy (anonymous):
yes
OpenStudy (amy0799):
so hit the 2nd button on it, its in light blue, and then the square root symbol, which is under the ^ symbol
OpenStudy (anonymous):
then what
OpenStudy (amy0799):
plug in 4900 into the square root
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OpenStudy (amy0799):
did you get it?
OpenStudy (anonymous):
1.001735585
OpenStudy (amy0799):
for the square root of 4900?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
no 70
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OpenStudy (anonymous):
70
OpenStudy (amy0799):
ok good, now plug in 70 into C=2pi(r)
r is 70
OpenStudy (anonymous):
i got 440
OpenStudy (amy0799):
yay! correct
OpenStudy (amy0799):
do you understand how to solve the rest now?
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OpenStudy (anonymous):
finally
OpenStudy (anonymous):
not really
OpenStudy (anonymous):
but i'll try
OpenStudy (amy0799):
do you still need my help?
OpenStudy (anonymous):
probably sorry
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OpenStudy (amy0799):
it's fine, can you try 4, you got the correct answer on this on 1, so it's the same setup
OpenStudy (anonymous):
can you tell me the steps one more time
OpenStudy (amy0799):
you are given the circumference, 12(4/7),
12(4/7)=2pi(r), solve for r and plug in the value of r into A=pi(r)^2
OpenStudy (amy0799):
tell me what you get for r first
OpenStudy (anonymous):
bro i know this sounds wrong but can you please give me the answers i have to go to bed
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OpenStudy (amy0799):
im sorry i cant do that, it's really not that hard
OpenStudy (amy0799):
ill give you some help
OpenStudy (amy0799):
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