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Mathematics 15 Online
OpenStudy (anonymous):

Please help with 4 questions ASAP medal+fan

OpenStudy (anonymous):

OpenStudy (anonymous):

2-5

OpenStudy (anonymous):

@mathmate @mathmale

OpenStudy (anonymous):

2-5

OpenStudy (anonymous):

Please help

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

@mathmate @mathwiz916 @mathmale @mathwizzard3 @MathematicalyExactOne

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

Can you please help

OpenStudy (anonymous):

2-5 on this attachment

OpenStudy (anonymous):

please help for fan and medal

OpenStudy (anonymous):

someone help!

OpenStudy (anonymous):

i am so confused i have been working for 3 hours and got 1 problem done

OpenStudy (amy0799):

ok, I think I know how to do this. Can you tell me what the area of a circle is? and the circumference of a circle is?

OpenStudy (anonymous):

a=pi times r

OpenStudy (anonymous):

c=2pi times r

OpenStudy (amy0799):

you forgot the squared for area. A=pi(r)^2

OpenStudy (amy0799):

for the first problem, you want to set the given circumference to the equation, 2pi(r) 352=2pi(r)

OpenStudy (anonymous):

oh yeah

OpenStudy (anonymous):

i got 9859

OpenStudy (anonymous):

but for 2-5 i didn't get

OpenStudy (amy0799):

It's basically the same set up. For 2, 3 1/7 = pi(r)^2, solve for r, and plug it into the C=2pi(r)

OpenStudy (anonymous):

what did you get

OpenStudy (amy0799):

i got C=1.0272

OpenStudy (anonymous):

Same

OpenStudy (anonymous):

Let's do number 3

OpenStudy (anonymous):

wait what did you get for number 1 i got 9859

OpenStudy (anonymous):

is that what you got?

OpenStudy (amy0799):

i got 9856

OpenStudy (anonymous):

that's what i got the first time

OpenStudy (amy0799):

that's due to rounding probably, i used 22/7 for pi

OpenStudy (anonymous):

what did you get for number 3

OpenStudy (amy0799):

did you already solve for it?

OpenStudy (anonymous):

not yet i'm about to

OpenStudy (amy0799):

i got my answer, tell me yours first

OpenStudy (anonymous):

i don't get this one

OpenStudy (anonymous):

i got something really off so i don't really want to say it

OpenStudy (anonymous):

how do i solve this

OpenStudy (amy0799):

the set up is exactly the same as question 2 15,400=2pi(r), solve for r and plug into C=2pi(r)

OpenStudy (anonymous):

how do you solve for r

OpenStudy (amy0799):

oops, that should be pi(r^2), because it's squared, you need to take the square root of it so \[\sqrt{15,400/22/7}\]

OpenStudy (anonymous):

i don't get this

OpenStudy (amy0799):

first solve for 15,400/2pi, what do you get? use 22/7 for pi

OpenStudy (amy0799):

i keep messing up, sorry, 15,400/pi

OpenStudy (anonymous):

i got this

OpenStudy (amy0799):

that's because you divided it the other way around divide 15,400 by 22/7 15,400/(22/7)

OpenStudy (anonymous):

100

OpenStudy (amy0799):

plug what i have typed exactly, with the parenthesis

OpenStudy (anonymous):

4900

OpenStudy (amy0799):

good, now you need to square root it

OpenStudy (anonymous):

24010000

OpenStudy (amy0799):

that's squaring it square root is \[\sqrt{4900}\]

OpenStudy (anonymous):

how do you square root it

OpenStudy (amy0799):

do you have a calculator?

OpenStudy (anonymous):

yes

OpenStudy (amy0799):

is it Texas Instruments TI-30X?

OpenStudy (anonymous):

yes

OpenStudy (amy0799):

so hit the 2nd button on it, its in light blue, and then the square root symbol, which is under the ^ symbol

OpenStudy (anonymous):

then what

OpenStudy (amy0799):

plug in 4900 into the square root

OpenStudy (amy0799):

did you get it?

OpenStudy (anonymous):

1.001735585

OpenStudy (amy0799):

for the square root of 4900?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

no 70

OpenStudy (anonymous):

70

OpenStudy (amy0799):

ok good, now plug in 70 into C=2pi(r) r is 70

OpenStudy (anonymous):

i got 440

OpenStudy (amy0799):

yay! correct

OpenStudy (amy0799):

do you understand how to solve the rest now?

OpenStudy (anonymous):

finally

OpenStudy (anonymous):

not really

OpenStudy (anonymous):

but i'll try

OpenStudy (amy0799):

do you still need my help?

OpenStudy (anonymous):

probably sorry

OpenStudy (amy0799):

it's fine, can you try 4, you got the correct answer on this on 1, so it's the same setup

OpenStudy (anonymous):

can you tell me the steps one more time

OpenStudy (amy0799):

you are given the circumference, 12(4/7), 12(4/7)=2pi(r), solve for r and plug in the value of r into A=pi(r)^2

OpenStudy (amy0799):

tell me what you get for r first

OpenStudy (anonymous):

bro i know this sounds wrong but can you please give me the answers i have to go to bed

OpenStudy (amy0799):

im sorry i cant do that, it's really not that hard

OpenStudy (amy0799):

ill give you some help

OpenStudy (amy0799):

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