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OpenStudy (anonymous):
Fill in the blank to make the expression a perfect square
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OpenStudy (anonymous):
v2+4v +
jimthompson5910 (jim_thompson5910):
Take half of \(\Large {\color{red}{4}}\) in \(\Large v^2 + {\color{red}{4}}v + \) to get what?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
now square that result
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OpenStudy (anonymous):
4
jimthompson5910 (jim_thompson5910):
so 4 goes in the blank
\[\Large v^2 + 4v + \underline{ \ \ 4 \ \ }\]
jimthompson5910 (jim_thompson5910):
The polynomial
\[\Large v^2 + 4v + 4\]
is a perfect square which factors to \(\Large (v+2)^2\)
OpenStudy (anonymous):
really?
OpenStudy (anonymous):
o ok i get it
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jimthompson5910 (jim_thompson5910):
yeah let's try another example
say I gave you this
v^2 + 10v + ________
jimthompson5910 (jim_thompson5910):
step 1) take half of 10 (the second coefficient)
step 2) square the result from step 1
what do you get?
OpenStudy (anonymous):
25
jimthompson5910 (jim_thompson5910):
yep so
v^2 + 10v + ________
turns into
v^2 + 10v + 25
jimthompson5910 (jim_thompson5910):
v^2 + 10v + 25 would factor to (v+5)^2
notice how the 10 cuts in half to 5
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OpenStudy (anonymous):
yeah i get it now . thank you so much :)
OpenStudy (anonymous):
make more sense now
jimthompson5910 (jim_thompson5910):
you're welcome
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