solve for 9x^2+36=0
First divide by 9 both side
Simplifying 9x2 + 36 = 0 Reorder the terms: 36 + 9x2 = 0 Solving 36 + 9x2 = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-36' to each side of the equation. 36 + -36 + 9x2 = 0 + -36 Combine like terms: 36 + -36 = 0 0 + 9x2 = 0 + -36 9x2 = 0 + -36 Combine like terms: 0 + -36 = -36 9x2 = -36 Divide each side by '9'. x2 = -4 Simplifying x2 = -4 Reorder the terms: 4 + x2 = -4 + 4 Combine like terms: -4 + 4 = 0 4 + x2 = 0
why was this necessary? Reorder the terms: 36 + 9x2 = 0
Note: 36+9x^2=0 has the form \[a^2+b^2=0, so.that.a^2=-b^2\]
... which means that any solutions are imaginary.
Also note that 36+9x^2 = 0 can be reduced by dividing all terms by 9. Try it.
\[9x ^{2}+36=0\] I think this much simplier.. Solving for X: 1) Transpose \[9x ^{2}=-36\] 2) x should have no coefficient (divide each side by the coefficient) \[9x^{2}/9 = -36/9\] \[x ^{2}=-4\] 3) Square root both sides (so that x would only be left) \[\sqrt{x^{2}}=\sqrt{-4}\] \[x=\sqrt{-4}\] ; there is no square for any negative number but you can write it as \[x=2i\]
i mean there is no square root for any negative number..
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