Question

Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

Part A: Find the average rate of change of each section. (4 points)
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

Answer 1

@rvc

Answer 2

@mathmate

Answer 3

I suspect the function is meant to be
\(2(3^x)\)
in which case the rates of change would be different between the two sections.

Answer 4

yes except 2(3) x on the top

Answer 5

average rate of change is given by \(\Delta y/\Delta x\), so for the first section,
average rate of change =\((f(1)-f(0))/(1-0)=(2*3^1-2*3^0)/(1-0)=4\)
You can calculate the average rate of change for the other interval similarly

Answer 6

i'm sorry i'm confused can u explain what u just did?

Answer 7

@mathmate

Answer 8

top is f(end)-f(start), bottom is end-start

Answer 9

what a coincidence..
what grade are u in??

Answer 10

9th

Answer 11

cool.

Answer 12

for section A first you need to find y (or find f(1) ,f(0)values when x=1 ,x=0
substitute x for 1 and 0 solve for y \[\rm f(1)=2(3)^1 \]
what would you get when u substitute x for 1 ???
f(1)= ?