At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?
66 handshakes. One person has two hands.. What do you think?
OMG That classic question!
First could you find number of combinations considering that each handshake requires 2 persons?
12 In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n. Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66. This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party. Since 66 is a relatively small number, you can also solve this problem with a hand calculator. Add 1 + 2 = + 3 = +... etc. until the total is 66. The last number that you entered (11) is n.
So you understood the answer?
yes lol
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