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Mathematics 14 Online
OpenStudy (horsegal244):

help

OpenStudy (horsegal244):

@bemoseemo

OpenStudy (bemoseemo):

ok so this one I will work you through this one I know a neat trick for it

OpenStudy (bemoseemo):

so the trick is see the two shorter sides? if you use this it will help find the diagonal side: 5^2+8^2=d^2 and d=diagonal side

OpenStudy (michele_laino):

hint: the requested distance is given by the perimeter of the triangle

OpenStudy (bemoseemo):

so 25+64=?^2

OpenStudy (bemoseemo):

if you can figure out ? you have the other side

OpenStudy (horsegal244):

ok so then the completed answer is 7,921?

OpenStudy (michele_laino):

we have this: distance \(d_1\) between Joan and Kash, is given by the distance between points \((0,6)\) and \((5,-2)\), so we can write: \[{d_1} = \sqrt {{{\left( {5 - 0} \right)}^2} + {{\left( { - 2 - 6} \right)}^2}} = ...?\]

OpenStudy (horsegal244):

Then i rind the square root right?

OpenStudy (bemoseemo):

25+64+?= total distance traveled and ? = 9.43

OpenStudy (horsegal244):

Is what he is saying right @Michele_Laino?

OpenStudy (bemoseemo):

oops sry I meant 5+8+?= total distance

OpenStudy (michele_laino):

yes! we have \(d_1=\sqrt{89}=9.43\)

OpenStudy (horsegal244):

13?

OpenStudy (horsegal244):

so 9 miles?

OpenStudy (bemoseemo):

so add those together and you should have your answer 5+8+9.43= 22.43 miles

OpenStudy (horsegal244):

so then is the answer 9 or 22

OpenStudy (bemoseemo):

22 if you round

OpenStudy (horsegal244):

ok ty

OpenStudy (michele_laino):

now we have to add these distances: distance between Joan and Gary, which is \(d_2=5-0=5\) and the distance between Kash and Gary, which is \(d_3=6-(-2)=8\) so we have: total distance = 9.43+5+8=...? and the answer of @bemoseemo is right!

OpenStudy (horsegal244):

i believe it is 4

OpenStudy (michele_laino):

here the requested distance is given by the distance between points \((0,2)\) and \((-3,-2)\), so we have: \[d = \sqrt {{{\left( { - 3 - 0} \right)}^2} + {{\left( { - 2 - 2} \right)}^2}} = \sqrt {9 + 16} = ...?\]

OpenStudy (horsegal244):

27

OpenStudy (horsegal244):

and the square root is 5

OpenStudy (michele_laino):

that's right! we can write this: \[\begin{gathered} d = \sqrt {{{\left( { - 3 - 0} \right)}^2} + {{\left( { - 2 - 2} \right)}^2}} = \sqrt {9 + 16} = \hfill \\ \hfill \\ = \sqrt {25} = 5 \hfill \\ \end{gathered} \]

OpenStudy (horsegal244):

This is the second to last one

OpenStudy (horsegal244):

that i need help with

OpenStudy (michele_laino):

here we have to apply the same formula, since such exercise, asks for the distance between points \((0,6)\) and \((7,-2)\), so we can write this: \[\begin{gathered} d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \hfill \\ \hfill \\ = \sqrt {{{\left( {7 - 0} \right)}^2} + {{\left( { - 2 - 6} \right)}^2}} = \sqrt {49 + 64} = ...? \hfill \\ \end{gathered} \]

OpenStudy (horsegal244):

113 and the sqaure root is 10.63

OpenStudy (michele_laino):

that's right!

OpenStudy (bemoseemo):

yep

OpenStudy (horsegal244):

Last one

OpenStudy (horsegal244):

is it b?

OpenStudy (michele_laino):

again we have to apply this formula: \[d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \] so, we can write: \[\begin{gathered} d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} = \hfill \\ \hfill \\ = \sqrt {{{\left( {4 - \left( { - 4} \right)} \right)}^2} + {{\left( {6 - \left( { - 2} \right)} \right)}^2}} = \sqrt {{8^2} + {8^2}} = \hfill \\ \hfill \\ = \sqrt {64 + 64} = ...? \hfill \\ \end{gathered} \]

OpenStudy (horsegal244):

lol 128 square root = 11.31

OpenStudy (horsegal244):

so D

OpenStudy (bemoseemo):

it should be d but I see how you may have gotten b

OpenStudy (michele_laino):

That's right!

OpenStudy (horsegal244):

thank you @Michele_Laino and @bemoseemo so much

OpenStudy (michele_laino):

:)

OpenStudy (bemoseemo):

no problem :D

OpenStudy (bemoseemo):

I game you a medal @Michele_Laino I definitely could not have explained as thorough as you did

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