celinegirl PLEASE CHECK MY ANSWER - C What is the product of Seven square root eight times four square root five? Simplify your answer. A.) Twenty eight radical ten B.) Fifty six radical two C.) Fifty six radical ten D.) Two hundred eighty radical four
\[(7\sqrt{8})(4\sqrt{5})\] With the help of the radical identity \(\sqrt{a.b}=\sqrt{a}.\sqrt{b}\) we can separate, but first, let's convert the 7 and the 4 as radicals: \[(\sqrt{49}\sqrt{8})(\sqrt{16}\sqrt{5})\] And then, applying the identity I spoke about we get: \[(\sqrt{49}\sqrt{8})(\sqrt{16}\sqrt{5}) \iff (\sqrt{(49)(8)})(\sqrt{(16)(5)})\] But then again, we can re-apply the identity since we still have the product of two radicals: \[(\sqrt{(49)(8)})(\sqrt{(16)(5)}) \iff \sqrt{(49)(8)(16)(5)}\] Al you have to do now is operate those multiplications inside the radical and you'll get the answer.
@Owlcoffee you may have confused me a little bit ha. The answer I came up with is wrong?
It's quite simple, when you want to express a radical into it's mosr simple form, you first express everything in one radical and then using the identity you can simplify it further: \[\sqrt{(49)(8)(16)(5)} \iff (7)(4)\sqrt{(8)(5)}\]
@Owlcoffee ohh okay
good job
\[280\sqrt{2}\]
??? @Owlcoffee
Show me your work
erm well thats the answer I got for \[(7) (4) \sqrt{(8) (5)}\]
is that wrong?
Show me how you operated the expression.
step by step.
is that necessary? I figured some out in my head and wrote some down..
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