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Mathematics 20 Online
OpenStudy (princessaurora):

** Por favor Will Fan & Medal ** Which statement about the end behavior of the logarithmic function f(x) = log(x + 3) – 2 is true? A) As x decreases, y moves toward the vertical asymptote at x = -3. B) As x decreases, y moves toward the vertical asymptote at x = -1 C) As x increases, y moves toward negative infinity. D) As x decreases, y moves toward positive infinity.

OpenStudy (anonymous):

looks hard for u

OpenStudy (anonymous):

its d

OpenStudy (anonymous):

its d

OpenStudy (princessaurora):

could you explain why please?

OpenStudy (princessaurora):

anyone?

OpenStudy (princessaurora):

Is there a rule that helps me determine the end behavior?

OpenStudy (anonymous):

The argument x+3 must be positive x+3 > 0 x > -3 Therefore, x cannot decrease below -3 As x approaches -3, log(x+3) approaches log(0) = -∞ As x approaches infinity, log(x+3) approaches infinity , so does log(x+3) -2 As x increases, f(x) moves toward infinity.

OpenStudy (princessaurora):

how do you know if it moves towards positive or negative infinity?

OpenStudy (princessaurora):

Like my problem that says as x decreases, y moves towards..?

OpenStudy (princessaurora):

how do i know?

OpenStudy (anonymous):

well Infinite Limit a function that increases or decreases without bound, moves toward infinity or negative infinity as x .

OpenStudy (anonymous):

that help?

OpenStudy (princessaurora):

yeah

OpenStudy (anonymous):

that it?

OpenStudy (princessaurora):

yeah that's it thanks for the help

OpenStudy (anonymous):

any time

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