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Mathematics 14 Online
OpenStudy (marie1738):

Can someone help me please?

OpenStudy (anonymous):

with ?

OpenStudy (anonymous):

?

zepdrix (zepdrix):

` Segments AC and DE are parallel.` This one is very important. If we don't have parallel sides, then the angles are not congruent. ` Angle B is congruent to itself due to the reflexive property.` This one is also very important. It might seem very obvious, but we are stating that The angle B in ABC is the same as angle B in DBE.

zepdrix (zepdrix):

Hmm let's see what else we have :)

zepdrix (zepdrix):

So that narrows it down to two choices, any ideas? :d

zepdrix (zepdrix):

Hmmm so do I. The fact that A+B is supplementary to angle C just tells us that it is a triangle. I don't really see how option D helps us in this proof either though... But I would lean towards A as the correct choice. Sorry I'm 100% on this one >.<

zepdrix (zepdrix):

not* 100% lol

zepdrix (zepdrix):

sure c:

zepdrix (zepdrix):

Geometry is my worst XD but we can try haha

zepdrix (zepdrix):

Same picture? :d

zepdrix (zepdrix):

Oh there is some type of flowchart that I don't see hehe

zepdrix (zepdrix):

So they start by showing that the sides are similar with the proportion they set up. Then they show that angle B is angle B. That's enough to give us SAS, so therefore the triangles are similar. So now we can say that corresponding parts of similar triangles must be similar. So which pair of angles do we want to match up to show that these lines are parallel? Hint: We want one angle from EACH triangle.

zepdrix (zepdrix):

|dw:1449766587460:dw|These two angles? Hmm no, I don't think that's going to do it.

zepdrix (zepdrix):

|dw:1449766706101:dw|Ah there we go :) Those are corresponding angles in our similar triangles. So yes, those will show parallel.

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