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Mathematics 9 Online
OpenStudy (anonymous):

one more question that needs checking @whpalmer4

OpenStudy (anonymous):

OpenStudy (anonymous):

i am pretty sure i am right @whpalmer4 , it is very similar to the question we did the first time

OpenStudy (anonymous):

the first answer is just the slope, and the second is me finding the slope y2-y1/x2-x1

OpenStudy (anonymous):

\[\frac{ 310-180 }{ 4-2 }\]

OpenStudy (anonymous):

= 65

OpenStudy (anonymous):

right?

OpenStudy (whpalmer4):

The first question asks you to find the slope of the plumber's wages, right? \[y=55x+85\]is the equation for the plumber's wages. Compare with slope-intercept form: \[y = mx+b\]where \(m\) is the slope $55 is the plumber's hourly rate, and he charges $85 for showing up.

OpenStudy (anonymous):

so:

OpenStudy (whpalmer4):

Second one can be computed the way you did, that gets the correct answer. You can also look at the table and see that the independent variable (the number of hours worked) goes from 1 to 2 as the wages go from 115 to 180, so the additional wages for 1 hour of work are 180-115 = 65. Knowing that the slope is 65, you can work out the entire formula for the electrician's wages: \[y = mx + b\]\[y = 65x + b\]but we now can plug in any data point from the table and find \(b\): \[115 = 65(1) + b]\[115 = 65 + b\]\[b = 50\] So the formula for the electrician is \[y = 65x + 50\]He charges $65/hour, and a $50 fee for showing up.

OpenStudy (anonymous):

nvm it is still 65

OpenStudy (whpalmer4):

sorry, fat fingered a bit of my formatting in that last post, but I think you can figure it out.

OpenStudy (anonymous):

@whpalmer4 tell me this:

OpenStudy (anonymous):

is thsi wrong that is all i need to know

OpenStudy (anonymous):

i dont have a lot of time right now so is it?

OpenStudy (anonymous):

it was right i got 100%

OpenStudy (anonymous):

here is medal!

OpenStudy (anonymous):

hope u get that starbucks!

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